Australian Open: tie-break fatal for Lorenzo Musetti, passes Ben Shelton

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Australian Open: Ben Shelton-Lorenzo Musetti 6-3 3-6 6-4 7-6

Lorenzo Musetti's adventure at the Australian Open ended in the round of 16. The Italian tennis player, in fact, è was beaten in four sets by the American Ben Shelton with the score of 6-3 3-6 6-4 7-6, after a battle of almost three hours.

The first set was decided already in the opening bars, as the American managed to go ahead immediately 3-0. On the strength of the break advantage, the world number 21 simply contained his opponent&#39s attempts to come back and closed the score at 6-3.

In the second set, after an initial balance, è Musetti found the decisive breakthrough thanks to three consecutive games that paved the way for the 6-3 final and to bring the match back to even score.

In the third set, both players were able to raise their service percentages, managing to hold their respective serves more easily. However, in the crucial stages of the set è still the blue to be less incisive and Shelton took advantage to find the break in the tenth game, which also gave him the set on the score of 6-4.

The fourth set starts in the worst way for the Carrara native, who loses three consecutive games. The world number 16, however, has a reaction of pride and finds in turn the counter-partial bringing himself back to par. The match, then, was decided at the tie-break, where è once again Shelton made the difference in the decisive moments.

In the round of 16, the American will face Gael Monfils, who surprisingly eliminated world number four Taylor Fritz.

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